For C' formula, is it C' = B' + (1 - alpha_B)A' instead of C' = B + (1 - alpha_B)A?
hm I agree, otherwise you wouldn't even end up using the alpha_A value
yes. it should be C'= B' + (1-alpha_B)A'.
For C' formula, is it C' = B' + (1 - alpha_B)A' instead of C' = B + (1 - alpha_B)A?
hm I agree, otherwise you wouldn't even end up using the alpha_A value
yes. it should be C'= B' + (1-alpha_B)A'.